HCF of 65 and 117 is the divisor that we get when the remainder becomes 0 after doing long division repeatedly. 1. Step 1: Divide117 (larger number) by 65 (smaller number). 2. Step 2:Since the remainder ≠ 0, we will divide the divisor of step 1 (65) by the remainder (52). 3. Step 3:Repeat this process until the … See more Prime factorization of 65 and 117 is (5 × 13) and (3 × 3 × 13) respectively. As visible, 65 and 117 have only one common prime factor i.e. 13. Hence, the HCF of 65 and 117 is 13. See more WebHCF of 196 and 38220; HCF of 65 and 117; HCF of 4 and 6; HCF of 616 and 32; HCF of 403, 434 and 465; HCF of 20 and 30; HCF of 18 and 24; HCF of 867 and 225; HCF of 12 and 18; Cuemath is one of the world's leading math learning platforms that offers LIVE 1-to-1 online math classes for grades K-12. Our mission is to transform the way children ...
If the hcf of 65 and 117 - Math Help
WebApr 7, 2024 · In the case of the two numbers 65 and 117, we have only one common prime factor which is 13. So, HCF of two numbers 65 and 117 = 13. According to equation (1), above equation becomes. ⇒ 65 n − 117 = 13. Now adding both the sides by 117, we get: ⇒ 65 n = 13 + 117. ⇒ 65 n = 130. WebStep 1: Find the HCF of 65 and 117. Using Euclid’s division algorithm, 117 = 65 × 1 + 52 ⇒ 65 = 52 × 1 + 13 ⇒ 52 = 13 × 4 + 0. Since the remainder has come to zero so the H.C.F. … mekanism fusion reactor 1.18
If the HCF of 65 and 117 can be expressed as (65m - Vedantu
WebHCF of 65, 117 is 13 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example. Consider we have numbers 65, 117 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where ... WebAug 3, 2024 · If the HCF of 65 and 117 is expressible in the form 65 m – 117, then the value of m is See answers Advertisement Advertisement Brainly User Brainly User Answer :- 2 Explanation: By Euclid’s division algorithm, b=aq+r 117=65×1+52 65=52×1+13 52=13×4+0 H.C.F(65,117) = 13 since, H.C.F 65m-117 so 65m - 117=113 WebLCM and HCF of 39 , 65 and 117 napa spearfish south dakota